What are the solutions to the equation solvefor x,cy^2=x^2+y ?

The solutions to the equation solvefor x,cy^2=x^2+y are x=sqrt(cy^2-y),x=-sqrt(cy^2-y)

Find the zeros of solvefor x,cy^2=x^2+y

The zeros of solvefor x,cy^2=x^2+y are x=sqrt(cy^2-y),x=-sqrt(cy^2-y)

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solve for

x, c y^{2} = x^{2} + y

x = c y^{2} - y, x = - c y^{2} - y

Solution steps

c y^{2} = x^{2} + y

Switch sides

x^{2} + y = c y^{2}

Move

y

to the right side

x^{2} = c y^{2} - y

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = c y^{2} - y, x = - c y^{2} - y

(2 - 3 x)^{2} = 0

5 x^{2} + 6 x = - 1

(x + 9) (x - 2) = 60

x, ln (y) = A x^{2} + B

2 x^{2} - 4 x = 12 x - 32

What are the solutions to the equation solvefor x,cy^2=x^2+y ?
The solutions to the equation solvefor x,cy^2=x^2+y are x=sqrt(cy^2-y),x=-sqrt(cy^2-y)
Find the zeros of solvefor x,cy^2=x^2+y
The zeros of solvefor x,cy^2=x^2+y are x=sqrt(cy^2-y),x=-sqrt(cy^2-y)