What are the solutions to the equation (4x-3)^2=16 ?

The solutions to the equation (4x-3)^2=16 are x= 7/4 ,x=-1/4

Find the zeros of (4x-3)^2=16

The zeros of (4x-3)^2=16 are x= 7/4 ,x=-1/4

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(4 x - 3)^{2} = 16

x = \frac{7}{4}, x = - \frac{1}{4}

Decimal Notation

x = 1.75, x = - 0.25

Solution steps

(4 x - 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 3 = 16 : x = \frac{7}{4}

Solve

4 x - 3 = - 16 : x = - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = - \frac{1}{4}

x^{2} - 14 x + 64 = 0

- x^{2} + 8 x + 5

x, m x^{2} + 2 x - 2 = 0

2 (x - 5)^{2} = 17

2 x^{2} - 12 x = 3

What are the solutions to the equation (4x-3)^2=16 ?
The solutions to the equation (4x-3)^2=16 are x= 7/4 ,x=-1/4
Find the zeros of (4x-3)^2=16
The zeros of (4x-3)^2=16 are x= 7/4 ,x=-1/4