What are the solutions to the equation -x^2-5x+25=-2x^2+5x ?

The solutions to the equation -x^2-5x+25=-2x^2+5x are x=5

Find the zeros of -x^2-5x+25=-2x^2+5x

The zeros of -x^2-5x+25=-2x^2+5x are x=5

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- x^{2} - 5 x + 25 = - 2 x^{2} + 5 x

x = 5

Solution steps

- x^{2} - 5 x + 25 = - 2 x^{2} + 5 x

Move

5 x

to the left side

- x^{2} - 10 x + 25 = - 2 x^{2}

Move

2 x^{2}

to the left side

x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

x = 5

The solution to the quadratic equation is:

x = 5

16 x^{2} - 24 x + 7 = 0

(w - 8) (w + 5) = 14

6 x^{2} - 8 x + 1

(r - 7)^{2} = 81

2 x^{2} - 7 x + 9 = (x - 3) (x + 1) + 3 x

What are the solutions to the equation -x^2-5x+25=-2x^2+5x ?
The solutions to the equation -x^2-5x+25=-2x^2+5x are x=5
Find the zeros of -x^2-5x+25=-2x^2+5x
The zeros of -x^2-5x+25=-2x^2+5x are x=5