What are the solutions to the equation 5x^2+20x+19=0 ?

The solutions to the equation 5x^2+20x+19=0 are x=(-10+sqrt(5))/5 ,x=-(10+sqrt(5))/5

Find the zeros of 5x^2+20x+19=0

The zeros of 5x^2+20x+19=0 are x=(-10+sqrt(5))/5 ,x=-(10+sqrt(5))/5

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5 x^{2} + 20 x + 19 = 0

x = \frac{- 10 + 5}{5}, x = - \frac{10 + 5}{5}

Decimal Notation

x = - 1.55278 \dots, x = - 2.44721 \dots

Solution steps

5 x^{2} + 20 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 5 \cdot 19}{2 \cdot 5}

2 0^{2} - 4 \cdot 5 \cdot 19 = 25

x_{1, 2} = \frac{- 20 \pm 2 5}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 20 + 2 5}{2 \cdot 5}, x_{2} = \frac{- 20 - 2 5}{2 \cdot 5}

x = \frac{- 20 + 2 5}{2 \cdot 5} : \frac{- 10 + 5}{5}

x = \frac{- 20 - 2 5}{2 \cdot 5} : - \frac{10 + 5}{5}

The solutions to the quadratic equation are:

x = \frac{- 10 + 5}{5}, x = - \frac{10 + 5}{5}

9 x^{2} - 125 = 0

x^{2} - b x + b^{2} = 0

r^{2} = 144

j (x) = - x^{2} + 3 x + 10, j (3 x - 2)

8 = 2 x^{2} - 5

What are the solutions to the equation 5x^2+20x+19=0 ?
The solutions to the equation 5x^2+20x+19=0 are x=(-10+sqrt(5))/5 ,x=-(10+sqrt(5))/5
Find the zeros of 5x^2+20x+19=0
The zeros of 5x^2+20x+19=0 are x=(-10+sqrt(5))/5 ,x=-(10+sqrt(5))/5