What are the solutions to the equation 8=2x^2-5 ?

The solutions to the equation 8=2x^2-5 are x=sqrt(13/2),x=-sqrt(13/2)

Find the zeros of 8=2x^2-5

The zeros of 8=2x^2-5 are x=sqrt(13/2),x=-sqrt(13/2)

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8 = 2 x^{2} - 5

x = \frac{13}{2}, x = - \frac{13}{2}

Solution steps

8 = 2 x^{2} - 5

Switch sides

2 x^{2} - 5 = 8

Move

5

to the right side

2 x^{2} = 13

Divide both sides by

2

x^{2} = \frac{13}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{13}{2}, x = - \frac{13}{2}

5 x (x - 3) + 9 = - 2 x (x - 3) + 7 x - 2

(x + 9)^{2} = - x - 7

6 x^{2} - 972 = 0

100 y^{2} - 20 y + 1 = 0

9 = 2 x^{2} - 5

What are the solutions to the equation 8=2x^2-5 ?
The solutions to the equation 8=2x^2-5 are x=sqrt(13/2),x=-sqrt(13/2)
Find the zeros of 8=2x^2-5
The zeros of 8=2x^2-5 are x=sqrt(13/2),x=-sqrt(13/2)