What are the solutions to the equation 9=2x^2-5 ?

The solutions to the equation 9=2x^2-5 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 9=2x^2-5

The zeros of 9=2x^2-5 are x=sqrt(7),x=-sqrt(7)

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9 = 2 x^{2} - 5

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

9 = 2 x^{2} - 5

Switch sides

2 x^{2} - 5 = 9

Move

5

to the right side

2 x^{2} = 14

Divide both sides by

2

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

x^{2} = a, a < 0

x^{2} = 8 x + 12

\frac{1}{2} x^{2} - x - 2 = 0

(2 x - 1)^{2} - x (x - 3) = 5

(2 x - 7)^{2} - 3 = 0

What are the solutions to the equation 9=2x^2-5 ?
The solutions to the equation 9=2x^2-5 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 9=2x^2-5
The zeros of 9=2x^2-5 are x=sqrt(7),x=-sqrt(7)