What are the solutions to the equation 15x^2+6x-14=0 ?

The solutions to the equation 15x^2+6x-14=0 are x=(-3+sqrt(219))/(15),x=-(3+sqrt(219))/(15)

Find the zeros of 15x^2+6x-14=0

The zeros of 15x^2+6x-14=0 are x=(-3+sqrt(219))/(15),x=-(3+sqrt(219))/(15)

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15 x^{2} + 6 x - 14 = 0

x = \frac{- 3 + 219}{15}, x = - \frac{3 + 219}{15}

Solution steps

15 x^{2} + 6 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 15 ( - 14 )}{2 \cdot 15}

6^{2} - 4 \cdot 15 (- 14) = 2219

x_{1, 2} = \frac{- 6 \pm 2 219}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 6 + 2 219}{2 \cdot 15}, x_{2} = \frac{- 6 - 2 219}{2 \cdot 15}

x = \frac{- 6 + 2 219}{2 \cdot 15} : \frac{- 3 + 219}{15}

x = \frac{- 6 - 2 219}{2 \cdot 15} : - \frac{3 + 219}{15}

The solutions to the quadratic equation are:

x = \frac{- 3 + 219}{15}, x = - \frac{3 + 219}{15}

x, x^{2} + y^{2} - 3 x y + 4 = 0

3 x (x - 2) = 10

(5 - x)^{2} + 2 x^{2} + 8 x - 20 = 0

x^{2} - 2 x - 323 = 0

2 x^{2} - 8 x - 16

What are the solutions to the equation 15x^2+6x-14=0 ?
The solutions to the equation 15x^2+6x-14=0 are x=(-3+sqrt(219))/(15),x=-(3+sqrt(219))/(15)
Find the zeros of 15x^2+6x-14=0
The zeros of 15x^2+6x-14=0 are x=(-3+sqrt(219))/(15),x=-(3+sqrt(219))/(15)