What are the solutions to the equation 3x(x-2)=10 ?

The solutions to the equation 3x(x-2)=10 are x=(3+sqrt(39))/3 ,x=(3-sqrt(39))/3

Find the zeros of 3x(x-2)=10

The zeros of 3x(x-2)=10 are x=(3+sqrt(39))/3 ,x=(3-sqrt(39))/3

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3 x (x - 2) = 10

x = \frac{3 + 39}{3}, x = \frac{3 - 39}{3}

Decimal Notation

x = 3.08166 \dots, x = - 1.08166 \dots

Solution steps

3 x (x - 2) = 10

Expand

3 x (x - 2) : 3 x^{2} - 6 x

3 x^{2} - 6 x = 10

Move

10

to the left side

3 x^{2} - 6 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 10) = 239

x_{1, 2} = \frac{- ( - 6 ) \pm 2 39}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 39}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 39}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 39}{2 \cdot 3} : \frac{3 + 39}{3}

x = \frac{- ( - 6 ) - 2 39}{2 \cdot 3} : \frac{3 - 39}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 39}{3}, x = \frac{3 - 39}{3}

(5 - x)^{2} + 2 x^{2} + 8 x - 20 = 0

x^{2} - 2 x - 323 = 0

2 x^{2} - 8 x - 16

2 x^{2} + b x + 2 = 0

2 y^{2} - 8 = 6 - 2 y^{2}

What are the solutions to the equation 3x(x-2)=10 ?
The solutions to the equation 3x(x-2)=10 are x=(3+sqrt(39))/3 ,x=(3-sqrt(39))/3
Find the zeros of 3x(x-2)=10
The zeros of 3x(x-2)=10 are x=(3+sqrt(39))/3 ,x=(3-sqrt(39))/3