What are the solutions to the equation 2y^2-8=6-2y^2 ?

The solutions to the equation 2y^2-8=6-2y^2 are y=sqrt(7/2),y=-sqrt(7/2)

Find the zeros of 2y^2-8=6-2y^2

The zeros of 2y^2-8=6-2y^2 are y=sqrt(7/2),y=-sqrt(7/2)

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2 y^{2} - 8 = 6 - 2 y^{2}

y = \frac{7}{2}, y = - \frac{7}{2}

Solution steps

2 y^{2} - 8 = 6 - 2 y^{2}

Move

8

to the right side

2 y^{2} = - 2 y^{2} + 14

Move

2 y^{2}

to the left side

4 y^{2} = 14

Divide both sides by

4

y^{2} = \frac{7}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{7}{2}, y = - \frac{7}{2}

x, \frac{x ^{2}}{18} = R

x, x^{2} y = 9

9 x^{2} - 30 x + 23 = 0

m^{2} + 12 = 48

4 x^{2} - b x + 9 = 0

What are the solutions to the equation 2y^2-8=6-2y^2 ?
The solutions to the equation 2y^2-8=6-2y^2 are y=sqrt(7/2),y=-sqrt(7/2)
Find the zeros of 2y^2-8=6-2y^2
The zeros of 2y^2-8=6-2y^2 are y=sqrt(7/2),y=-sqrt(7/2)