What are the solutions to the equation m^2+12=48 ?

The solutions to the equation m^2+12=48 are m=6,m=-6

Find the zeros of m^2+12=48

The zeros of m^2+12=48 are m=6,m=-6

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m^{2} + 12 = 48

m = 6, m = - 6

Solution steps

m^{2} + 12 = 48

Move

12

to the right side

m^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 36, m = - 36

36 = 6

- 36 = - 6

m = 6, m = - 6

4 x^{2} - b x + 9 = 0

8 x^{2} + 14 x = 0

0.2 x^{2} - 1.1 x - 1 = 0

n^{2} + 10 = 7 n

2 x^{2} - 6 x + c = 0

What are the solutions to the equation m^2+12=48 ?
The solutions to the equation m^2+12=48 are m=6,m=-6
Find the zeros of m^2+12=48
The zeros of m^2+12=48 are m=6,m=-6