What are the solutions to the equation 15ax^2+6x-3ax=0 ?

The solutions to the equation 15ax^2+6x-3ax=0 are x=0,x=(a-2)/(5a);\quad a\ne 0

Find the zeros of 15ax^2+6x-3ax=0

The zeros of 15ax^2+6x-3ax=0 are x=0,x=(a-2)/(5a);\quad a\ne 0

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15 a x^{2} + 6 x - 3 a x = 0

x = 0, x = \frac{a - 2}{5 a}; a \neq = 0

Solution steps

15 a x^{2} + 6 x - 3 a x = 0

Factor

15 a x^{2} + 6 x - 3 a x : 3 x (5 a x - a + 2)

3 x (5 a x - a + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 5 a x - a + 2 = 0

Solve

5 a x - a + 2 = 0 : x = \frac{a - 2}{5 a}; a \neq = 0

The solutions to the quadratic equation are:

x = 0, x = \frac{a - 2}{5 a}; a \neq = 0

x^{2} - 3 x - 8 = x + 4

3 x (1 - 2 x) = 16

5 x^{2} - 2 = - 9 x

x^{2} + 70 = 17 x

t (t) = 25 - 2 t

What are the solutions to the equation 15ax^2+6x-3ax=0 ?
The solutions to the equation 15ax^2+6x-3ax=0 are x=0,x=(a-2)/(5a);\quad a\ne 0
Find the zeros of 15ax^2+6x-3ax=0
The zeros of 15ax^2+6x-3ax=0 are x=0,x=(a-2)/(5a);\quad a\ne 0