What are the solutions to the equation x^2+70=17x ?

The solutions to the equation x^2+70=17x are x=10,x=7

Find the zeros of x^2+70=17x

The zeros of x^2+70=17x are x=10,x=7

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x^{2} + 70 = 17 x

x = 10, x = 7

Solution steps

x^{2} + 70 = 17 x

Move

17 x

to the left side

x^{2} + 70 - 17 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 17 x + 70 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 70}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 70 = 3

x_{1, 2} = \frac{- ( - 17 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 17 ) - 3}{2 \cdot 1}

x = \frac{- ( - 17 ) + 3}{2 \cdot 1} : 10

x = \frac{- ( - 17 ) - 3}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

x = 10, x = 7

t (t) = 25 - 2 t

2 + 3 (2 x + 1) (2 x - 1) = 3

10 - 4 x - x^{2}

x^{2} - 4 x - 20 = - 5 x

(2 - x)^{2} - (2 x - 3)^{2} = 50

What are the solutions to the equation x^2+70=17x ?
The solutions to the equation x^2+70=17x are x=10,x=7
Find the zeros of x^2+70=17x
The zeros of x^2+70=17x are x=10,x=7