What are the solutions to the equation x^2-25x+475=0 ?

The solutions to the equation x^2-25x+475=0 are x= 25/2+i(5sqrt(51))/2 ,x= 25/2-i(5sqrt(51))/2

Find the zeros of x^2-25x+475=0

The zeros of x^2-25x+475=0 are x= 25/2+i(5sqrt(51))/2 ,x= 25/2-i(5sqrt(51))/2

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x^{2} - 25 x + 475 = 0

x = \frac{25}{2} + i \frac{5 51}{2}, x = \frac{25}{2} - i \frac{5 51}{2}

Solution steps

x^{2} - 25 x + 475 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 1 \cdot 475}{2 \cdot 1}

Simplify

(- 25)^{2} - 4 \cdot 1 \cdot 475 : 551 i

x_{1, 2} = \frac{- ( - 25 ) \pm 5 51 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 5 51 i}{2 \cdot 1}, x_{2} = \frac{- ( - 25 ) - 5 51 i}{2 \cdot 1}

x = \frac{- ( - 25 ) + 5 51 i}{2 \cdot 1} : \frac{25}{2} + i \frac{5 51}{2}

x = \frac{- ( - 25 ) - 5 51 i}{2 \cdot 1} : \frac{25}{2} - i \frac{5 51}{2}

The solutions to the quadratic equation are:

x = \frac{25}{2} + i \frac{5 51}{2}, x = \frac{25}{2} - i \frac{5 51}{2}

x^{2} + 3^{3} = 31

(11 x + 13)^{2} - 4 (11 x + 13) - 21 = 0

(5 - x) (2 x + 3) = 0

3 x^{2} - 132 = 0

(3 - x) (1 + 2 x) = - 9

What are the solutions to the equation x^2-25x+475=0 ?
The solutions to the equation x^2-25x+475=0 are x= 25/2+i(5sqrt(51))/2 ,x= 25/2-i(5sqrt(51))/2
Find the zeros of x^2-25x+475=0
The zeros of x^2-25x+475=0 are x= 25/2+i(5sqrt(51))/2 ,x= 25/2-i(5sqrt(51))/2