What are the solutions to the equation x(x+7)=14 ?

The solutions to the equation x(x+7)=14 are x=(-7+sqrt(105))/2 ,x=(-7-sqrt(105))/2

Find the zeros of x(x+7)=14

The zeros of x(x+7)=14 are x=(-7+sqrt(105))/2 ,x=(-7-sqrt(105))/2

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x (x + 7) = 14

x = \frac{- 7 + 105}{2}, x = \frac{- 7 - 105}{2}

Solution steps

x (x + 7) = 14

Expand

x (x + 7) : x^{2} + 7 x

x^{2} + 7 x = 14

Move

14

to the left side

x^{2} + 7 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 14) = 105

x_{1, 2} = \frac{- 7 \pm 105}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 105}{2 \cdot 1}, x_{2} = \frac{- 7 - 105}{2 \cdot 1}

x = \frac{- 7 + 105}{2 \cdot 1} : \frac{- 7 + 105}{2}

x = \frac{- 7 - 105}{2 \cdot 1} : \frac{- 7 - 105}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 105}{2}, x = \frac{- 7 - 105}{2}

(2 x + 1)^{2} - (x + 2) = x (x + 2) + 3

(x + 8)^{2} = - x - 2

3 x^{2} + 7 x - 6 = 0

(3 x + 2) (2 x - 5) = (4 x - 1) (5 x + 6)

x^{2} = - 31

What are the solutions to the equation x(x+7)=14 ?
The solutions to the equation x(x+7)=14 are x=(-7+sqrt(105))/2 ,x=(-7-sqrt(105))/2
Find the zeros of x(x+7)=14
The zeros of x(x+7)=14 are x=(-7+sqrt(105))/2 ,x=(-7-sqrt(105))/2