What are the solutions to the equation 5t^2+3t-2=0 ?

The solutions to the equation 5t^2+3t-2=0 are t= 2/5 ,t=-1

Find the zeros of 5t^2+3t-2=0

The zeros of 5t^2+3t-2=0 are t= 2/5 ,t=-1

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5 t^{2} + 3 t - 2 = 0

t = \frac{2}{5}, t = - 1

Solution steps

5 t^{2} + 3 t - 2 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

3^{2} - 4 \cdot 5 (- 2) = 7

t_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- 3 + 7}{2 \cdot 5}, t_{2} = \frac{- 3 - 7}{2 \cdot 5}

t = \frac{- 3 + 7}{2 \cdot 5} : \frac{2}{5}

t = \frac{- 3 - 7}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

t = \frac{2}{5}, t = - 1

25 x^{2} + 30 x + 12

t, h = v t - g t^{2}

9 x^{2} - 12 x - 14 = 0

x^{2} - 13 x + 1 = - 9 x + 6

x^{2} + 3 x + 10

What are the solutions to the equation 5t^2+3t-2=0 ?
The solutions to the equation 5t^2+3t-2=0 are t= 2/5 ,t=-1
Find the zeros of 5t^2+3t-2=0
The zeros of 5t^2+3t-2=0 are t= 2/5 ,t=-1