What are the solutions to the equation x^2-13x+1=-9x+6 ?

The solutions to the equation x^2-13x+1=-9x+6 are x=5,x=-1

Find the zeros of x^2-13x+1=-9x+6

The zeros of x^2-13x+1=-9x+6 are x=5,x=-1

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x^{2} - 13 x + 1 = - 9 x + 6

x = 5, x = - 1

Solution steps

x^{2} - 13 x + 1 = - 9 x + 6

Move

6

to the left side

x^{2} - 13 x - 5 = - 9 x

Move

9 x

to the left side

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

x^{2} + 3 x + 10

x, x^{2} = a x y + b y

2 x^{2} - 7 x - 8 = 12

2 x^{2} - 12 x + 15

- 4 x^{2} + 151.8 x - 396.8 = 0

What are the solutions to the equation x^2-13x+1=-9x+6 ?
The solutions to the equation x^2-13x+1=-9x+6 are x=5,x=-1
Find the zeros of x^2-13x+1=-9x+6
The zeros of x^2-13x+1=-9x+6 are x=5,x=-1