What are the solutions to the equation 2x^2-7x-8=12 ?

The solutions to the equation 2x^2-7x-8=12 are x=(7+sqrt(209))/4 ,x=(7-sqrt(209))/4

Find the zeros of 2x^2-7x-8=12

The zeros of 2x^2-7x-8=12 are x=(7+sqrt(209))/4 ,x=(7-sqrt(209))/4

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2 x^{2} - 7 x - 8 = 12

x = \frac{7 + 209}{4}, x = \frac{7 - 209}{4}

Solution steps

2 x^{2} - 7 x - 8 = 12

Move

12

to the left side

2 x^{2} - 7 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 20) = 209

x_{1, 2} = \frac{- ( - 7 ) \pm 209}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 209}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 209}{2 \cdot 2}

x = \frac{- ( - 7 ) + 209}{2 \cdot 2} : \frac{7 + 209}{4}

x = \frac{- ( - 7 ) - 209}{2 \cdot 2} : \frac{7 - 209}{4}

The solutions to the quadratic equation are:

x = \frac{7 + 209}{4}, x = \frac{7 - 209}{4}

2 x^{2} - 12 x + 15

- 4 x^{2} + 151.8 x - 396.8 = 0

(2 x + 3)^{2} = 169

c x^{2} - 6 x + 3 = 0

2 x^{2} - 7 x + 30 = 0

What are the solutions to the equation 2x^2-7x-8=12 ?
The solutions to the equation 2x^2-7x-8=12 are x=(7+sqrt(209))/4 ,x=(7-sqrt(209))/4
Find the zeros of 2x^2-7x-8=12
The zeros of 2x^2-7x-8=12 are x=(7+sqrt(209))/4 ,x=(7-sqrt(209))/4