What are the solutions to the equation (2x+3)^2=169 ?

The solutions to the equation (2x+3)^2=169 are x=5,x=-8

Find the zeros of (2x+3)^2=169

The zeros of (2x+3)^2=169 are x=5,x=-8

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(2 x + 3)^{2} = 169

x = 5, x = - 8

Solution steps

(2 x + 3)^{2} = 169

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 = 169 : x = 5

Solve

2 x + 3 = - 169 : x = - 8

The solutions to the quadratic equation are:

x = 5, x = - 8

c x^{2} - 6 x + 3 = 0

2 x^{2} - 7 x + 30 = 0

2 s^{2} - 16 = - 88

x (4 x - 9) + 5 = 0

3 x^{2} - 12 x + 17

What are the solutions to the equation (2x+3)^2=169 ?
The solutions to the equation (2x+3)^2=169 are x=5,x=-8
Find the zeros of (2x+3)^2=169
The zeros of (2x+3)^2=169 are x=5,x=-8