What are the solutions to the equation x(4x-9)+5=0 ?

The solutions to the equation x(4x-9)+5=0 are x= 5/4 ,x=1

Find the zeros of x(4x-9)+5=0

The zeros of x(4x-9)+5=0 are x= 5/4 ,x=1

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x (4 x - 9) + 5 = 0

x = \frac{5}{4}, x = 1

Solution steps

x (4 x - 9) + 5 = 0

Expand

x (4 x - 9) + 5 : 4 x^{2} - 9 x + 5

4 x^{2} - 9 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 \cdot 5 = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 4}

x = \frac{- ( - 9 ) + 1}{2 \cdot 4} : \frac{5}{4}

x = \frac{- ( - 9 ) - 1}{2 \cdot 4} : 1

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = 1

3 x^{2} - 12 x + 17

x^{2} - 3 x - 4 = 2 x

x, x + y = x^{2} - y^{2}

(4 x + 7)^{2} = 44

35 - 6 x = 8 x^{2}

What are the solutions to the equation x(4x-9)+5=0 ?
The solutions to the equation x(4x-9)+5=0 are x= 5/4 ,x=1
Find the zeros of x(4x-9)+5=0
The zeros of x(4x-9)+5=0 are x= 5/4 ,x=1