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What are the solutions to the equation (4x+7)^2=44 ?
The solutions to the equation (4x+7)^2=44 are x=(2sqrt(11)-7)/4 ,x=(-2sqrt(11)-7)/4Find the zeros of (4x+7)^2=44
The zeros of (4x+7)^2=44 are x=(2sqrt(11)-7)/4 ,x=(-2sqrt(11)-7)/4