What are the solutions to the equation 2x^2=10x-25 ?

The solutions to the equation 2x^2=10x-25 are x= 5/2+i 5/2 ,x= 5/2-i 5/2

Find the zeros of 2x^2=10x-25

The zeros of 2x^2=10x-25 are x= 5/2+i 5/2 ,x= 5/2-i 5/2

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2 x^{2} = 10 x - 25

x = \frac{5}{2} + i \frac{5}{2}, x = \frac{5}{2} - i \frac{5}{2}

Solution steps

2 x^{2} = 10 x - 25

Move

25

to the left side

2 x^{2} + 25 = 10 x

Move

10 x

to the left side

2 x^{2} + 25 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 25}{2 \cdot 2}

Simplify

(- 10)^{2} - 4 \cdot 2 \cdot 25 : 10 i

x_{1, 2} = \frac{- ( - 10 ) \pm 10 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 10 i}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 10 i}{2 \cdot 2}

x = \frac{- ( - 10 ) + 10 i}{2 \cdot 2} : \frac{5}{2} + i \frac{5}{2}

x = \frac{- ( - 10 ) - 10 i}{2 \cdot 2} : \frac{5}{2} - i \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{5}{2}, x = \frac{5}{2} - i \frac{5}{2}

x^{2} - (k + 2) x + k + 1 = 0

x^{2} - 5 = 3 x

(x - 13)^{2} = 400

x^{2} - 3 x - 0.9 = 0

4 + 7 x - x^{2} = - \frac{x}{2}

What are the solutions to the equation 2x^2=10x-25 ?
The solutions to the equation 2x^2=10x-25 are x= 5/2+i 5/2 ,x= 5/2-i 5/2
Find the zeros of 2x^2=10x-25
The zeros of 2x^2=10x-25 are x= 5/2+i 5/2 ,x= 5/2-i 5/2