What are the solutions to the equation 4x^2-11x=7 ?

The solutions to the equation 4x^2-11x=7 are x=(11+sqrt(233))/8 ,x=(11-sqrt(233))/8

Find the zeros of 4x^2-11x=7

The zeros of 4x^2-11x=7 are x=(11+sqrt(233))/8 ,x=(11-sqrt(233))/8

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4 x^{2} - 11 x = 7

x = \frac{11 + 233}{8}, x = \frac{11 - 233}{8}

Solution steps

4 x^{2} - 11 x = 7

Move

7

to the left side

4 x^{2} - 11 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 11)^{2} - 4 \cdot 4 (- 7) = 233

x_{1, 2} = \frac{- ( - 11 ) \pm 233}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 233}{2 \cdot 4}, x_{2} = \frac{- ( - 11 ) - 233}{2 \cdot 4}

x = \frac{- ( - 11 ) + 233}{2 \cdot 4} : \frac{11 + 233}{8}

x = \frac{- ( - 11 ) - 233}{2 \cdot 4} : \frac{11 - 233}{8}

The solutions to the quadratic equation are:

x = \frac{11 + 233}{8}, x = \frac{11 - 233}{8}

7 c^{2} = c + 6

4 c^{2} + c - 6 = 0

9 x + 28 = 9 x^{2}

11 x = 3 x^{2} - 9

x, x^{2} - 4 x + 2^{t} = 0

What are the solutions to the equation 4x^2-11x=7 ?
The solutions to the equation 4x^2-11x=7 are x=(11+sqrt(233))/8 ,x=(11-sqrt(233))/8
Find the zeros of 4x^2-11x=7
The zeros of 4x^2-11x=7 are x=(11+sqrt(233))/8 ,x=(11-sqrt(233))/8