What are the solutions to the equation X^2+5X+2=-4 ?

The solutions to the equation X^2+5X+2=-4 are X=-2,X=-3

Find the zeros of X^2+5X+2=-4

The zeros of X^2+5X+2=-4 are X=-2,X=-3

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X^{2} + 5 X + 2 = - 4

X = - 2, X = - 3

Solution steps

X^{2} + 5 X + 2 = - 4

Move

4

to the left side

X^{2} + 5 X + 6 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

X_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 5 + 1}{2 \cdot 1}, X_{2} = \frac{- 5 - 1}{2 \cdot 1}

X = \frac{- 5 + 1}{2 \cdot 1} : - 2

X = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

X = - 2, X = - 3

- 4 x^{2} - 24 x - 40

3 x^{2} - 18 x + 17

x, x^{2} = x y

49 - (2 x)^{2} = 0

x^{2} + 15 x + 90 = - 4 x

What are the solutions to the equation X^2+5X+2=-4 ?
The solutions to the equation X^2+5X+2=-4 are X=-2,X=-3
Find the zeros of X^2+5X+2=-4
The zeros of X^2+5X+2=-4 are X=-2,X=-3