What are the solutions to the equation 49-(2x)^2=0 ?

The solutions to the equation 49-(2x)^2=0 are x= 7/2 ,x=-7/2

Find the zeros of 49-(2x)^2=0

The zeros of 49-(2x)^2=0 are x= 7/2 ,x=-7/2

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49 - (2 x)^{2} = 0

x = \frac{7}{2}, x = - \frac{7}{2}

Decimal Notation

x = 3.5, x = - 3.5

Solution steps

49 - (2 x)^{2} = 0

Expand

49 - (2 x)^{2} : 49 - 4 x^{2}

49 - 4 x^{2} = 0

Move

49

to the right side

- 4 x^{2} = - 49

Divide both sides by

- 4

x^{2} = \frac{49}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{49}{4}, x = - \frac{49}{4}

\frac{49}{4} = \frac{7}{2}

- \frac{49}{4} = - \frac{7}{2}

x = \frac{7}{2}, x = - \frac{7}{2}

x^{2} + 15 x + 90 = - 4 x

24 x^{2} - 2 x + 10 = 0

3 (x - 7) = x (x - 7)

y^{2} + 13 y + 40 = 0

300 = t^{2} + 2 t

What are the solutions to the equation 49-(2x)^2=0 ?
The solutions to the equation 49-(2x)^2=0 are x= 7/2 ,x=-7/2
Find the zeros of 49-(2x)^2=0
The zeros of 49-(2x)^2=0 are x= 7/2 ,x=-7/2