What are the solutions to the equation 3x^2+x+3=0 ?

The solutions to the equation 3x^2+x+3=0 are x=-1/6+i(sqrt(35))/6 ,x=-1/6-i(sqrt(35))/6

Find the zeros of 3x^2+x+3=0

The zeros of 3x^2+x+3=0 are x=-1/6+i(sqrt(35))/6 ,x=-1/6-i(sqrt(35))/6

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3 x^{2} + x + 3 = 0

x = - \frac{1}{6} + i \frac{35}{6}, x = - \frac{1}{6} - i \frac{35}{6}

Solution steps

3 x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

Simplify

1^{2} - 4 \cdot 3 \cdot 3 : 35 i

x_{1, 2} = \frac{- 1 \pm 35 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 35 i}{2 \cdot 3}, x_{2} = \frac{- 1 - 35 i}{2 \cdot 3}

x = \frac{- 1 + 35 i}{2 \cdot 3} : - \frac{1}{6} + i \frac{35}{6}

x = \frac{- 1 - 35 i}{2 \cdot 3} : - \frac{1}{6} - i \frac{35}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{6} + i \frac{35}{6}, x = - \frac{1}{6} - i \frac{35}{6}

2 x + 4 + x = 8 + 2 (3 + x) - 3

(m + 3)^{2} = 0

2 x - x^{2}

(7 x + 4)^{2} = 4

12 a \geq - 24

What are the solutions to the equation 3x^2+x+3=0 ?
The solutions to the equation 3x^2+x+3=0 are x=-1/6+i(sqrt(35))/6 ,x=-1/6-i(sqrt(35))/6
Find the zeros of 3x^2+x+3=0
The zeros of 3x^2+x+3=0 are x=-1/6+i(sqrt(35))/6 ,x=-1/6-i(sqrt(35))/6