What are the solutions to the equation 5a^2+20a+20=0 ?

The solutions to the equation 5a^2+20a+20=0 are a=-2

Find the zeros of 5a^2+20a+20=0

The zeros of 5a^2+20a+20=0 are a=-2

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5 a^{2} + 20 a + 20 = 0

a = - 2

Solution steps

5 a^{2} + 20 a + 20 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 5 \cdot 20}{2 \cdot 5}

2 0^{2} - 4 \cdot 5 \cdot 20 = 0

a_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 5}

a = \frac{- 20}{2 \cdot 5}

\frac{- 20}{2 \cdot 5} = - 2

a = - 2

The solution to the quadratic equation is:

a = - 2

x, x^{2} = 2 x y - 1

0 = x^{2} + 7 x - 44

x^{2} = 531 mod 2021

3 x^{2} + 10 x = 2 x - 4

(2 x + 3) (x - 2) = 2

What are the solutions to the equation 5a^2+20a+20=0 ?
The solutions to the equation 5a^2+20a+20=0 are a=-2
Find the zeros of 5a^2+20a+20=0
The zeros of 5a^2+20a+20=0 are a=-2