What are the solutions to the equation 0=x^2+7x-44 ?

The solutions to the equation 0=x^2+7x-44 are x=4,x=-11

Find the zeros of 0=x^2+7x-44

The zeros of 0=x^2+7x-44 are x=4,x=-11

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0 = x^{2} + 7 x - 44

x = 4, x = - 11

Solution steps

0 = x^{2} + 7 x - 44

Switch sides

x^{2} + 7 x - 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 44 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 44) = 15

x_{1, 2} = \frac{- 7 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 15}{2 \cdot 1}, x_{2} = \frac{- 7 - 15}{2 \cdot 1}

x = \frac{- 7 + 15}{2 \cdot 1} : 4

x = \frac{- 7 - 15}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 4, x = - 11

x^{2} = 531 mod 2021

3 x^{2} + 10 x = 2 x - 4

(2 x + 3) (x - 2) = 2

(x - 32)^{2} = 56

x (3 x - 7) = 6

What are the solutions to the equation 0=x^2+7x-44 ?
The solutions to the equation 0=x^2+7x-44 are x=4,x=-11
Find the zeros of 0=x^2+7x-44
The zeros of 0=x^2+7x-44 are x=4,x=-11