What are the solutions to the equation x(x+5)=12 ?

The solutions to the equation x(x+5)=12 are x=(-5+sqrt(73))/2 ,x=(-5-sqrt(73))/2

Find the zeros of x(x+5)=12

The zeros of x(x+5)=12 are x=(-5+sqrt(73))/2 ,x=(-5-sqrt(73))/2

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x (x + 5) = 12

x = \frac{- 5 + 73}{2}, x = \frac{- 5 - 73}{2}

Decimal Notation

x = 1.77200 \dots, x = - 6.77200 \dots

Solution steps

x (x + 5) = 12

Expand

x (x + 5) : x^{2} + 5 x

x^{2} + 5 x = 12

Move

12

to the left side

x^{2} + 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 12) = 73

x_{1, 2} = \frac{- 5 \pm 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 73}{2 \cdot 1}, x_{2} = \frac{- 5 - 73}{2 \cdot 1}

x = \frac{- 5 + 73}{2 \cdot 1} : \frac{- 5 + 73}{2}

x = \frac{- 5 - 73}{2 \cdot 1} : \frac{- 5 - 73}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 73}{2}, x = \frac{- 5 - 73}{2}

x^{2} - 6 x - 160 = 0

x^{2} + 3 = 100

3 x^{2} - 72 = 2 x^{2} + 28

x, 2 x^{2} + 4 x + 1 = 0

x^{2} = 18 x - 59

What are the solutions to the equation x(x+5)=12 ?
The solutions to the equation x(x+5)=12 are x=(-5+sqrt(73))/2 ,x=(-5-sqrt(73))/2
Find the zeros of x(x+5)=12
The zeros of x(x+5)=12 are x=(-5+sqrt(73))/2 ,x=(-5-sqrt(73))/2