What are the solutions to the equation x^2-6x-160=0 ?

The solutions to the equation x^2-6x-160=0 are x=16,x=-10

Find the zeros of x^2-6x-160=0

The zeros of x^2-6x-160=0 are x=16,x=-10

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x^{2} - 6 x - 160 = 0

x = 16, x = - 10

Solution steps

x^{2} - 6 x - 160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 160 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 160) = 26

x_{1, 2} = \frac{- ( - 6 ) \pm 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 26}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 26}{2 \cdot 1}

x = \frac{- ( - 6 ) + 26}{2 \cdot 1} : 16

x = \frac{- ( - 6 ) - 26}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 16, x = - 10

x^{2} + 3 = 100

3 x^{2} - 72 = 2 x^{2} + 28

x, 2 x^{2} + 4 x + 1 = 0

x^{2} = 18 x - 59

0.01 x^{2} + 0.2 x - 0.6 = 0

What are the solutions to the equation x^2-6x-160=0 ?
The solutions to the equation x^2-6x-160=0 are x=16,x=-10
Find the zeros of x^2-6x-160=0
The zeros of x^2-6x-160=0 are x=16,x=-10