What are the solutions to the equation 0.01x^2+0.2x-0.6=0 ?

The solutions to the equation 0.01x^2+0.2x-0.6=0 are x=2(2sqrt(10)-5),x=-2(5+2sqrt(10))

Find the zeros of 0.01x^2+0.2x-0.6=0

The zeros of 0.01x^2+0.2x-0.6=0 are x=2(2sqrt(10)-5),x=-2(5+2sqrt(10))

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0.01 x^{2} + 0.2 x - 0.6 = 0

x = 2 (210 - 5), x = - 2 (5 + 210)

Decimal Notation

x = 2.64911 \dots, x = - 22.64911 \dots

Solution steps

0.01 x^{2} + 0.2 x - 0.6 = 0

Multiply both sides by

100

x^{2} + 20 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 60) = 810

x_{1, 2} = \frac{- 20 \pm 8 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 8 10}{2 \cdot 1}, x_{2} = \frac{- 20 - 8 10}{2 \cdot 1}

x = \frac{- 20 + 8 10}{2 \cdot 1} : 2 (210 - 5)

x = \frac{- 20 - 8 10}{2 \cdot 1} : - 2 (5 + 210)

The solutions to the quadratic equation are:

x = 2 (210 - 5), x = - 2 (5 + 210)

(2 w + 3) w = 77

x (x + 11) = 2 (x + 5)

3 x^{2} + 33 x + 84 = 0

x^{2} - 56 = 25

3 x^{2} + 2 x = 18 x + 12

What are the solutions to the equation 0.01x^2+0.2x-0.6=0 ?
The solutions to the equation 0.01x^2+0.2x-0.6=0 are x=2(2sqrt(10)-5),x=-2(5+2sqrt(10))
Find the zeros of 0.01x^2+0.2x-0.6=0
The zeros of 0.01x^2+0.2x-0.6=0 are x=2(2sqrt(10)-5),x=-2(5+2sqrt(10))