What are the solutions to the equation 3x^2+33x+84=0 ?

The solutions to the equation 3x^2+33x+84=0 are x=-4,x=-7

Find the zeros of 3x^2+33x+84=0

The zeros of 3x^2+33x+84=0 are x=-4,x=-7

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3 x^{2} + 33 x + 84 = 0

x = - 4, x = - 7

Solution steps

3 x^{2} + 33 x + 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 33 \pm 3 3 ^{2} - 4 \cdot 3 \cdot 84}{2 \cdot 3}

3 3^{2} - 4 \cdot 3 \cdot 84 = 9

x_{1, 2} = \frac{- 33 \pm 9}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 33 + 9}{2 \cdot 3}, x_{2} = \frac{- 33 - 9}{2 \cdot 3}

x = \frac{- 33 + 9}{2 \cdot 3} : - 4

x = \frac{- 33 - 9}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = - 4, x = - 7

x^{2} - 56 = 25

3 x^{2} + 2 x = 18 x + 12

3 x = - x^{2} + 7

(2 x + 1) (2 x - 3) + x = (x - 5)^{2} - 22

1.5 x - 0.12 x^{2} = 0

What are the solutions to the equation 3x^2+33x+84=0 ?
The solutions to the equation 3x^2+33x+84=0 are x=-4,x=-7
Find the zeros of 3x^2+33x+84=0
The zeros of 3x^2+33x+84=0 are x=-4,x=-7