What are the solutions to the equation 1.5x-0.12x^2=0 ?

The solutions to the equation 1.5x-0.12x^2=0 are x=0,x= 25/2

Find the zeros of 1.5x-0.12x^2=0

The zeros of 1.5x-0.12x^2=0 are x=0,x= 25/2

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1.5 x - 0.12 x^{2} = 0

x = 0, x = \frac{25}{2}

Decimal Notation

x = 0, x = 12.5

Solution steps

1.5 x - 0.12 x^{2} = 0

Multiply both sides by

100

150 x - 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 12 x^{2} + 150 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 150 \pm 15 0 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

15 0^{2} - 4 (- 12) \cdot 0 = 150

x_{1, 2} = \frac{- 150 \pm 150}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 150 + 150}{2 ( - 12 )}, x_{2} = \frac{- 150 - 150}{2 ( - 12 )}

x = \frac{- 150 + 150}{2 ( - 12 )} : 0

x = \frac{- 150 - 150}{2 ( - 12 )} : \frac{25}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{25}{2}

6 k^{2} + 7 k - 11 = 5 k^{2}

x^{2} - 0.7 x + 0.1 = 0

m^{2} + 3 m = 4

(x + 4) (x - 2) = 4 x

(x + 7)^{2} = 289

What are the solutions to the equation 1.5x-0.12x^2=0 ?
The solutions to the equation 1.5x-0.12x^2=0 are x=0,x= 25/2
Find the zeros of 1.5x-0.12x^2=0
The zeros of 1.5x-0.12x^2=0 are x=0,x= 25/2