What are the solutions to the equation (x+7)^2=289 ?

The solutions to the equation (x+7)^2=289 are x=10,x=-24

Find the zeros of (x+7)^2=289

The zeros of (x+7)^2=289 are x=10,x=-24

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(x + 7)^{2} = 289

x = 10, x = - 24

Solution steps

(x + 7)^{2} = 289

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 289 : x = 10

Solve

x + 7 = - 289 : x = - 24

The solutions to the quadratic equation are:

x = 10, x = - 24

5 x^{2} = 5 x + 6

4 x^{2} + 72 x + 324 = 5 x^{2} + 48 x + 144

x, x^{2} = 3 x y - 6

9 x = 3 x^{2}

- 18 - 3 x + 6 x^{2} = 0

What are the solutions to the equation (x+7)^2=289 ?
The solutions to the equation (x+7)^2=289 are x=10,x=-24
Find the zeros of (x+7)^2=289
The zeros of (x+7)^2=289 are x=10,x=-24