What are the solutions to the equation 5x^2+2x-3+9x=0 ?

The solutions to the equation 5x^2+2x-3+9x=0 are x=(-11+sqrt(181))/(10),x=(-11-sqrt(181))/(10)

Find the zeros of 5x^2+2x-3+9x=0

The zeros of 5x^2+2x-3+9x=0 are x=(-11+sqrt(181))/(10),x=(-11-sqrt(181))/(10)

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5 x^{2} + 2 x - 3 + 9 x = 0

x = \frac{- 11 + 181}{10}, x = \frac{- 11 - 181}{10}

Decimal Notation

x = 0.24536 \dots, x = - 2.44536 \dots

Solution steps

5 x^{2} + 2 x - 3 + 9 x = 0

Refine

5 x^{2} + 11 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

1 1^{2} - 4 \cdot 5 (- 3) = 181

x_{1, 2} = \frac{- 11 \pm 181}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 11 + 181}{2 \cdot 5}, x_{2} = \frac{- 11 - 181}{2 \cdot 5}

x = \frac{- 11 + 181}{2 \cdot 5} : \frac{- 11 + 181}{10}

x = \frac{- 11 - 181}{2 \cdot 5} : \frac{- 11 - 181}{10}

The solutions to the quadratic equation are:

x = \frac{- 11 + 181}{10}, x = \frac{- 11 - 181}{10}

D, g = b (a + D^{2})

4 (x + 3)^{2} + 2 = - 6

(x + 3) (x - 3) = x (4 x + 5)

y, y^{2} = 5 - X

3 (x^{2} + 1) = x (x - 3)

What are the solutions to the equation 5x^2+2x-3+9x=0 ?
The solutions to the equation 5x^2+2x-3+9x=0 are x=(-11+sqrt(181))/(10),x=(-11-sqrt(181))/(10)
Find the zeros of 5x^2+2x-3+9x=0
The zeros of 5x^2+2x-3+9x=0 are x=(-11+sqrt(181))/(10),x=(-11-sqrt(181))/(10)