What are the solutions to the equation (x+2)^2-5=0 ?

The solutions to the equation (x+2)^2-5=0 are x=sqrt(5)-2,x=-sqrt(5)-2

Find the zeros of (x+2)^2-5=0

The zeros of (x+2)^2-5=0 are x=sqrt(5)-2,x=-sqrt(5)-2

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(x + 2)^{2} - 5 = 0

x = 5 - 2, x = - 5 - 2

Decimal Notation

x = 0.23606 \dots, x = - 4.23606 \dots

Solution steps

(x + 2)^{2} - 5 = 0

Move

5

to the right side

(x + 2)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 5 : x = 5 - 2

Solve

x + 2 = - 5 : x = - 5 - 2

The solutions to the quadratic equation are:

x = 5 - 2, x = - 5 - 2

x^{2} + 9 = 16

8 a^{2} = 17 a

x^{2} - 9 x + \frac{81}{4} = 0

a^{2} - 16 = 32

(3 x + 2)^{2} = 49

What are the solutions to the equation (x+2)^2-5=0 ?
The solutions to the equation (x+2)^2-5=0 are x=sqrt(5)-2,x=-sqrt(5)-2
Find the zeros of (x+2)^2-5=0
The zeros of (x+2)^2-5=0 are x=sqrt(5)-2,x=-sqrt(5)-2