What are the solutions to the equation -q^2+3q-2=0 ?

The solutions to the equation -q^2+3q-2=0 are q=1,q=2

Find the zeros of -q^2+3q-2=0

The zeros of -q^2+3q-2=0 are q=1,q=2

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- q^{2} + 3 q - 2 = 0

q = 1, q = 2

Solution steps

- q^{2} + 3 q - 2 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

3^{2} - 4 (- 1) (- 2) = 1

q_{1, 2} = \frac{- 3 \pm 1}{2 ( - 1 )}

Separate the solutions

q_{1} = \frac{- 3 + 1}{2 ( - 1 )}, q_{2} = \frac{- 3 - 1}{2 ( - 1 )}

q = \frac{- 3 + 1}{2 ( - 1 )} : 1

q = \frac{- 3 - 1}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

q = 1, q = 2

25 x^{2} - 30 x + 13 = 0

t, x = \frac{1}{2} a t^{2}

y, x = y^{2} - y

1 - 3 x^{2} = 2 (x - 1)

m (x) = 3 x^{2} + x - 5, m (\frac{1}{2})

What are the solutions to the equation -q^2+3q-2=0 ?
The solutions to the equation -q^2+3q-2=0 are q=1,q=2
Find the zeros of -q^2+3q-2=0
The zeros of -q^2+3q-2=0 are q=1,q=2