What are the solutions to the equation 25x^2-30x+13=0 ?

The solutions to the equation 25x^2-30x+13=0 are x= 3/5+i 2/5 ,x= 3/5-i 2/5

Find the zeros of 25x^2-30x+13=0

The zeros of 25x^2-30x+13=0 are x= 3/5+i 2/5 ,x= 3/5-i 2/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 x^{2} - 30 x + 13 = 0

x = \frac{3}{5} + i \frac{2}{5}, x = \frac{3}{5} - i \frac{2}{5}

Solution steps

25 x^{2} - 30 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 25 \cdot 13}{2 \cdot 25}

Simplify

(- 30)^{2} - 4 \cdot 25 \cdot 13 : 20 i

x_{1, 2} = \frac{- ( - 30 ) \pm 20 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 20 i}{2 \cdot 25}, x_{2} = \frac{- ( - 30 ) - 20 i}{2 \cdot 25}

x = \frac{- ( - 30 ) + 20 i}{2 \cdot 25} : \frac{3}{5} + i \frac{2}{5}

x = \frac{- ( - 30 ) - 20 i}{2 \cdot 25} : \frac{3}{5} - i \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{3}{5} + i \frac{2}{5}, x = \frac{3}{5} - i \frac{2}{5}

t, x = \frac{1}{2} a t^{2}

y, x = y^{2} - y

1 - 3 x^{2} = 2 (x - 1)

m (x) = 3 x^{2} + x - 5, m (\frac{1}{2})

- x^{2} = - 81 x

What are the solutions to the equation 25x^2-30x+13=0 ?
The solutions to the equation 25x^2-30x+13=0 are x= 3/5+i 2/5 ,x= 3/5-i 2/5
Find the zeros of 25x^2-30x+13=0
The zeros of 25x^2-30x+13=0 are x= 3/5+i 2/5 ,x= 3/5-i 2/5