What are the solutions to the equation -x^2=-81x ?

The solutions to the equation -x^2=-81x are x=0,x=81

Find the zeros of -x^2=-81x

The zeros of -x^2=-81x are x=0,x=81

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- x^{2} = - 81 x

x = 0, x = 81

Solution steps

- x^{2} = - 81 x

Move

81 x

to the left side

- x^{2} + 81 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 81 \pm 8 1 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

8 1^{2} - 4 (- 1) \cdot 0 = 81

x_{1, 2} = \frac{- 81 \pm 81}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 81 + 81}{2 ( - 1 )}, x_{2} = \frac{- 81 - 81}{2 ( - 1 )}

x = \frac{- 81 + 81}{2 ( - 1 )} : 0

x = \frac{- 81 - 81}{2 ( - 1 )} : 81

The solutions to the quadratic equation are:

x = 0, x = 81

(11 x - 1)^{2} - 2 (11 x - 1) - 3 = 0

26 t^{2} - 355 t + 300 = 0

10 x^{2} + 24 x - 130 = 0

x^{2} - 3 x + 4 = 2 x^{2} - 7 x - 8

(1 - x) (10 - x) - 9 = 0

What are the solutions to the equation -x^2=-81x ?
The solutions to the equation -x^2=-81x are x=0,x=81
Find the zeros of -x^2=-81x
The zeros of -x^2=-81x are x=0,x=81