What are the solutions to the equation (1-x)(10-x)-9=0 ?

The solutions to the equation (1-x)(10-x)-9=0 are x=(11+3sqrt(13))/2 ,x=(11-3sqrt(13))/2

Find the zeros of (1-x)(10-x)-9=0

The zeros of (1-x)(10-x)-9=0 are x=(11+3sqrt(13))/2 ,x=(11-3sqrt(13))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1 - x) (10 - x) - 9 = 0

x = \frac{11 + 3 13}{2}, x = \frac{11 - 3 13}{2}

Decimal Notation

x = 10.90832 \dots, x = 0.09167 \dots

Solution steps

(1 - x) (10 - x) - 9 = 0

Expand

(1 - x) (10 - x) - 9 : x^{2} - 11 x + 1

x^{2} - 11 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 1 = 313

x_{1, 2} = \frac{- ( - 11 ) \pm 3 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 3 13}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 3 13}{2 \cdot 1}

x = \frac{- ( - 11 ) + 3 13}{2 \cdot 1} : \frac{11 + 3 13}{2}

x = \frac{- ( - 11 ) - 3 13}{2 \cdot 1} : \frac{11 - 3 13}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 3 13}{2}, x = \frac{11 - 3 13}{2}

(2 x + 4)^{2} = 5

49 x^{2} + 1 = 25

5 x^{2} - 30 x + 25 = 0

x - x^{2} + 3 = 4 x^{2} + 2

2 x (5 x - 3) = 0

What are the solutions to the equation (1-x)(10-x)-9=0 ?
The solutions to the equation (1-x)(10-x)-9=0 are x=(11+3sqrt(13))/2 ,x=(11-3sqrt(13))/2
Find the zeros of (1-x)(10-x)-9=0
The zeros of (1-x)(10-x)-9=0 are x=(11+3sqrt(13))/2 ,x=(11-3sqrt(13))/2