What are the solutions to the equation 2x^2+4x+6=0 ?

The solutions to the equation 2x^2+4x+6=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

Find the zeros of 2x^2+4x+6=0

The zeros of 2x^2+4x+6=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

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2 x^{2} + 4 x + 6 = 0

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

2 x^{2} + 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

4^{2} - 4 \cdot 2 \cdot 6 : 42 i

x_{1, 2} = \frac{- 4 \pm 4 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 4 2 i}{2 \cdot 2}, x_{2} = \frac{- 4 - 4 2 i}{2 \cdot 2}

x = \frac{- 4 + 4 2 i}{2 \cdot 2} : - 1 + 2 i

x = \frac{- 4 - 4 2 i}{2 \cdot 2} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

1.2 (x + 7.5) = 2.5 x - 17

x^{2} = 5 x + 6

x^{2} + 16 x + 5 = 0

(4 x^{2} y)^{3}

- 7 + 6 x = x + 8

What are the solutions to the equation 2x^2+4x+6=0 ?
The solutions to the equation 2x^2+4x+6=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i
Find the zeros of 2x^2+4x+6=0
The zeros of 2x^2+4x+6=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i