What are the solutions to the equation (100-2x)(50-2x)=3600 ?

The solutions to the equation (100-2x)(50-2x)=3600 are x=70,x=5

Find the zeros of (100-2x)(50-2x)=3600

The zeros of (100-2x)(50-2x)=3600 are x=70,x=5

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(100 - 2 x) (50 - 2 x) = 3600

x = 70, x = 5

Solution steps

(100 - 2 x) (50 - 2 x) = 3600

Expand

(100 - 2 x) (50 - 2 x) : 5000 - 300 x + 4 x^{2}

5000 - 300 x + 4 x^{2} = 3600

Move

3600

to the left side

4 x^{2} - 300 x + 1400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 300 ) \pm ( - 300 ) ^{2} - 4 \cdot 4 \cdot 1400}{2 \cdot 4}

(- 300)^{2} - 4 \cdot 4 \cdot 1400 = 260

x_{1, 2} = \frac{- ( - 300 ) \pm 260}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 300 ) + 260}{2 \cdot 4}, x_{2} = \frac{- ( - 300 ) - 260}{2 \cdot 4}

x = \frac{- ( - 300 ) + 260}{2 \cdot 4} : 70

x = \frac{- ( - 300 ) - 260}{2 \cdot 4} : 5

The solutions to the quadratic equation are:

x = 70, x = 5

(c + 1)^{2} = \frac{21}{2}

x^{2} + 8 = - 6 x

- 5 (t^{2} - 3) + 15 = - 2 t

x^{2} + 6 x - 21 = 0

x^{2} = 15 - 2 x

What are the solutions to the equation (100-2x)(50-2x)=3600 ?
The solutions to the equation (100-2x)(50-2x)=3600 are x=70,x=5
Find the zeros of (100-2x)(50-2x)=3600
The zeros of (100-2x)(50-2x)=3600 are x=70,x=5