What are the solutions to the equation 25x^2+121=0 ?

The solutions to the equation 25x^2+121=0 are x= 11/5 i,x=-11/5 i

Find the zeros of 25x^2+121=0

The zeros of 25x^2+121=0 are x= 11/5 i,x=-11/5 i

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25 x^{2} + 121 = 0

x = \frac{11}{5} i, x = - \frac{11}{5} i

Solution steps

25 x^{2} + 121 = 0

Move

121

to the right side

25 x^{2} = - 121

Divide both sides by

25

x^{2} = - \frac{121}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{121}{25}, x = - - \frac{121}{25}

- \frac{121}{25} = \frac{11}{5} i

- - \frac{121}{25} = - \frac{11}{5} i

x = \frac{11}{5} i, x = - \frac{11}{5} i

9 x^{2} = 324

s (11 - s) = 24

5 x^{2} - 3 (2 x - 1) = 2 x^{2} - 8 x

8 x^{2} - 24 = 8

2 x^{2} - 3 x + 4 = x^{2} + 5 x - 3

What are the solutions to the equation 25x^2+121=0 ?
The solutions to the equation 25x^2+121=0 are x= 11/5 i,x=-11/5 i
Find the zeros of 25x^2+121=0
The zeros of 25x^2+121=0 are x= 11/5 i,x=-11/5 i