What are the solutions to the equation w^2-4w-3=0 ?

The solutions to the equation w^2-4w-3=0 are w=2+sqrt(7),w=2-sqrt(7)

Find the zeros of w^2-4w-3=0

The zeros of w^2-4w-3=0 are w=2+sqrt(7),w=2-sqrt(7)

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w^{2} - 4 w - 3 = 0

w = 2 + 7, w = 2 - 7

Decimal Notation

w = 4.64575 \dots, w = - 0.64575 \dots

Solution steps

w^{2} - 4 w - 3 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 3) = 27

w_{1, 2} = \frac{- ( - 4 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 4 ) + 2 7}{2 \cdot 1}, w_{2} = \frac{- ( - 4 ) - 2 7}{2 \cdot 1}

w = \frac{- ( - 4 ) + 2 7}{2 \cdot 1} : 2 + 7

w = \frac{- ( - 4 ) - 2 7}{2 \cdot 1} : 2 - 7

The solutions to the quadratic equation are:

w = 2 + 7, w = 2 - 7

3 (x^{2} - 2 x + 4) = 0

- 3 (t - 1)^{2} + 12 = 0

- x^{2} + 9 = 25

x^{2} + 23 - 140 = 0

x, x y^{3} = - 3 x^{2} y^{4}

What are the solutions to the equation w^2-4w-3=0 ?
The solutions to the equation w^2-4w-3=0 are w=2+sqrt(7),w=2-sqrt(7)
Find the zeros of w^2-4w-3=0
The zeros of w^2-4w-3=0 are w=2+sqrt(7),w=2-sqrt(7)