What are the solutions to the equation -x^2+9=25 ?

The solutions to the equation -x^2+9=25 are x=4i,x=-4i

Find the zeros of -x^2+9=25

The zeros of -x^2+9=25 are x=4i,x=-4i

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- x^{2} + 9 = 25

x = 4 i, x = - 4 i

Solution steps

- x^{2} + 9 = 25

Move

9

to the right side

- x^{2} = 16

Divide both sides by

- 1

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

x^{2} + 23 - 140 = 0

x, x y^{3} = - 3 x^{2} y^{4}

3 r^{2} = 18

m^{2} = 225

3 x^{2} - 6 x = - 5

What are the solutions to the equation -x^2+9=25 ?
The solutions to the equation -x^2+9=25 are x=4i,x=-4i
Find the zeros of -x^2+9=25
The zeros of -x^2+9=25 are x=4i,x=-4i