What are the solutions to the equation (2x+3)(x-3)=0 ?

The solutions to the equation (2x+3)(x-3)=0 are x=-3/2 ,x=3

Find the zeros of (2x+3)(x-3)=0

The zeros of (2x+3)(x-3)=0 are x=-3/2 ,x=3

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(2 x + 3) (x - 3) = 0

x = - \frac{3}{2}, x = 3

Decimal Notation

x = - 1.5, x = 3

Solution steps

(2 x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or x - 3 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 3

4 x^{2} - x = 2 x^{2} + 7 x

3 x^{2} - 6 x + 15

2 x^{2} + 20 + 10 x = 4 x^{2} + 28

X^{2} - 2 (X) (4) - (- 4)^{2} = 2 (X + 8)

(5 p + 3)^{2} = 8

What are the solutions to the equation (2x+3)(x-3)=0 ?
The solutions to the equation (2x+3)(x-3)=0 are x=-3/2 ,x=3
Find the zeros of (2x+3)(x-3)=0
The zeros of (2x+3)(x-3)=0 are x=-3/2 ,x=3