What are the solutions to the equation 4(u+1)^2=18 ?

The solutions to the equation 4(u+1)^2=18 are u= 3/(sqrt(2))-1,u=-3/(sqrt(2))-1

Find the zeros of 4(u+1)^2=18

The zeros of 4(u+1)^2=18 are u= 3/(sqrt(2))-1,u=-3/(sqrt(2))-1

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4 (u + 1)^{2} = 18

u = \frac{3}{2} - 1, u = - \frac{3}{2} - 1

Decimal Notation

u = 1.12132 \dots, u = - 3.12132 \dots

Solution steps

4 (u + 1)^{2} = 18

Divide both sides by

4

(u + 1)^{2} = \frac{9}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

u + 1 = \frac{9}{2} : u = \frac{3}{2} - 1

Solve

u + 1 = - \frac{9}{2} : u = - \frac{3}{2} - 1

The solutions to the quadratic equation are:

u = \frac{3}{2} - 1, u = - \frac{3}{2} - 1

s^{2} - 30 s + 205 = - 46

75 d^{2} + 25 d = 0

4 p^{2} - 5 p - 1 = 4 p

y^{2} + 20 (y + 5) = 0

x^{2} + 5 x - 16 = 0

What are the solutions to the equation 4(u+1)^2=18 ?
The solutions to the equation 4(u+1)^2=18 are u= 3/(sqrt(2))-1,u=-3/(sqrt(2))-1
Find the zeros of 4(u+1)^2=18
The zeros of 4(u+1)^2=18 are u= 3/(sqrt(2))-1,u=-3/(sqrt(2))-1