What are the solutions to the equation 8y^2-15=4y^2+1 ?

The solutions to the equation 8y^2-15=4y^2+1 are y=2,y=-2

Find the zeros of 8y^2-15=4y^2+1

The zeros of 8y^2-15=4y^2+1 are y=2,y=-2

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8 y^{2} - 15 = 4 y^{2} + 1

y = 2, y = - 2

Solution steps

8 y^{2} - 15 = 4 y^{2} + 1

Move

15

to the right side

8 y^{2} = 4 y^{2} + 16

Move

4 y^{2}

to the left side

4 y^{2} = 16

Divide both sides by

4

y^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 4, y = - 4

4 = 2

- 4 = - 2

y = 2, y = - 2

3 x (2 x - 1) = 6

2 (3 x + 1)^{2} = 0

- 2 x^{2} + 2 x + 40 = 0

- \frac{9.81}{2} t^{2} + 10 t + 45 = 0

2 X + 1 = 8 X^{2}

What are the solutions to the equation 8y^2-15=4y^2+1 ?
The solutions to the equation 8y^2-15=4y^2+1 are y=2,y=-2
Find the zeros of 8y^2-15=4y^2+1
The zeros of 8y^2-15=4y^2+1 are y=2,y=-2