What are the solutions to the equation 2(3x+1)^2=0 ?

The solutions to the equation 2(3x+1)^2=0 are x=-1/3

Find the zeros of 2(3x+1)^2=0

The zeros of 2(3x+1)^2=0 are x=-1/3

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2 (3 x + 1)^{2} = 0

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

2 (3 x + 1)^{2} = 0

Divide both sides by

2

(3 x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

The solution to the quadratic equation is:

x = - \frac{1}{3}

- 2 x^{2} + 2 x + 40 = 0

- \frac{9.81}{2} t^{2} + 10 t + 45 = 0

2 X + 1 = 8 X^{2}

x, x^{2} - 8 x + b y + 8 = 0

(x + 6)^{2} = - 1

What are the solutions to the equation 2(3x+1)^2=0 ?
The solutions to the equation 2(3x+1)^2=0 are x=-1/3
Find the zeros of 2(3x+1)^2=0
The zeros of 2(3x+1)^2=0 are x=-1/3