What are the solutions to the equation (x-5)(3x+4)=0 ?

The solutions to the equation (x-5)(3x+4)=0 are x=5,x=-4/3

Find the zeros of (x-5)(3x+4)=0

The zeros of (x-5)(3x+4)=0 are x=5,x=-4/3

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(x - 5) (3 x + 4) = 0

x = 5, x = - \frac{4}{3}

Decimal Notation

x = 5, x = - 1.33333 \dots

Solution steps

(x - 5) (3 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or 3 x + 4 = 0

Solve

x - 5 = 0 : x = 5

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

The solutions to the quadratic equation are:

x = 5, x = - \frac{4}{3}

4 x^{2} + 12 x = - 17

(6 - R)^{2} + (3 - R)^{2} = R^{2}

x^{2} + 11 x - 30 = 0

n = - h^{2} + \frac{7}{a}

- 15 x^{2} + x + 28 = 0

What are the solutions to the equation (x-5)(3x+4)=0 ?
The solutions to the equation (x-5)(3x+4)=0 are x=5,x=-4/3
Find the zeros of (x-5)(3x+4)=0
The zeros of (x-5)(3x+4)=0 are x=5,x=-4/3