What are the solutions to the equation 4(x^2-2)-3(x^2-1)=20 ?

The solutions to the equation 4(x^2-2)-3(x^2-1)=20 are x=5,x=-5

Find the zeros of 4(x^2-2)-3(x^2-1)=20

The zeros of 4(x^2-2)-3(x^2-1)=20 are x=5,x=-5

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4 (x^{2} - 2) - 3 (x^{2} - 1) = 20

x = 5, x = - 5

Solution steps

4 (x^{2} - 2) - 3 (x^{2} - 1) = 20

Expand

4 (x^{2} - 2) - 3 (x^{2} - 1) : x^{2} - 5

x^{2} - 5 = 20

Move

5

to the right side

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

x, 36 y^{2} + x^{2} + 36 z = 9

5 x^{2} + 2 x + 6 = 0

x, y^{2} = 12 x^{2}

6 x - 2 x^{2} = 10

225 x^{2} - 16 = 33

What are the solutions to the equation 4(x^2-2)-3(x^2-1)=20 ?
The solutions to the equation 4(x^2-2)-3(x^2-1)=20 are x=5,x=-5
Find the zeros of 4(x^2-2)-3(x^2-1)=20
The zeros of 4(x^2-2)-3(x^2-1)=20 are x=5,x=-5